What is the solution for derivative of y=24sqrt(x) ?

The solution for derivative of y=24sqrt(x) is y=16x^{3/2}+c_{1}

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derivative of y=24sqrt(x)

\frac{d}{d x} y = 24 x

y = 16 x^{\frac{3}{2}} + c_{1}

Solution steps

\frac{d y}{d x} = 24 x

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 24 x d x

\int 24 x d x = 16 x^{\frac{3}{2}} + c_{1}

y = 16 x^{\frac{3}{2}} + c_{1}

x \to 0 lim (2 x sin (\frac{1}{x}))

y^{^{'}} = \frac{e ^{y} + 1}{e ^{y}}

x \to 3 lim (x^{3} + 3 x^{2} - x + 2)

x^{2} - 7, 6 x

\frac{d}{d x} (3 e^{1 - x^{2}})

What is the solution for derivative of y=24sqrt(x) ?
The solution for derivative of y=24sqrt(x) is y=16x^{3/2}+c_{1}