What is the limit as x approaches 2 of sqrt(f(x)) ?

The limit as x approaches 2 of sqrt(f(x)) is sqrt(f(2))

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limit as x approaches 2 of sqrt(f(x))

x \to 2 lim (f (x))

f (2)

Solution steps

x \to 2 lim (f (x))

Plug in the value

x = 2

, assuming the function is continuous at this point

= f (2)

f (x) = \frac{0.3 ( 9 ^{x} )}{x ^{3}}

y^{^{''}} - 4 y^{^{'}} + 4 y = (12 x^{2} - 6 x) e^{2} x

n = 1 \sum \infty \frac{8 ^{n}}{n !}

\int \frac{x}{3 x + 2} d x

8 x - x^{2}

What is the limit as x approaches 2 of sqrt(f(x)) ?
The limit as x approaches 2 of sqrt(f(x)) is sqrt(f(2))