What is the tangent of y=cos(x),\at x=-pi/2 ?

The tangent of y=cos(x),\at x=-pi/2 is y=x+pi/2

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tangent of y=cos(x),\at x=-pi/2

tangent of

y = cos (x), at x = - \frac{π}{2}

y = x + \frac{π}{2}

Solution steps

Find the tangent point:

(- \frac{π}{2}, 0)

Find the slope of

y = cos (x) : \frac{d y}{d x} = - sin (x)

Compute the slope of

y = cos (x)

x = - \frac{π}{2} : m = 1

Find the line with slope m=

1

and passing through

(- \frac{π}{2}, 0) : y = x + \frac{π}{2}

y = x + \frac{π}{2}

x \to 0 lim (e^{x} - 2 x^{2})

\frac{\partial}{\partial x} (4 x^{2} + 3 y^{2})

y^{2} \cdot (\frac{d y}{d x}) + y^{3} = 1

\int \frac{x ^{3} + 1}{x ^{2} + 5 x + 6} d x

What is the tangent of y=cos(x),\at x=-pi/2 ?
The tangent of y=cos(x),\at x=-pi/2 is y=x+pi/2