What is the sum from n=1 to infinity of ne^{-5n} ?

The sum from n=1 to infinity of ne^{-5n} is converges

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sum from n=1 to infinity of ne^{-5n}

n = 1 \sum \infty n e^{- 5 n}

converges

Solution steps

n = 1 \sum \infty n e^{- 5 n}

Apply Series Ratio Test:

converges

= converges

cos^{4} (θ + 9)

y = x^{4} + 4 e^{x}, (0, 4)

\frac{d}{d x} ((\frac{1 - 2 x}{1 + x})^{3})

\frac{d}{d x} (\frac{4 x}{7 - tan ( x )})

\int_{0}^{5} \frac{1}{x ^{\frac{17}{16}}} d x

What is the sum from n=1 to infinity of ne^{-5n} ?
The sum from n=1 to infinity of ne^{-5n} is converges