What is the integral from-2 to-1 of 4/(x^2) ?

The integral from-2 to-1 of 4/(x^2) is 2

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integral from-2 to-1 of 4/(x^2)

\int_{- 2}^{- 1} \frac{4}{x ^{2}} d x

2

Solution steps

\int_{- 2}^{- 1} \frac{4}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{- 2}^{- 1} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{- 2}^{- 1}

= 4 [- \frac{1}{x}]_{- 2}^{- 1}

Compute the boundaries:

\frac{1}{2}

= 4 \cdot \frac{1}{2}

Simplify

= 2

(13) (1 - 10)

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What is the integral from-2 to-1 of 4/(x^2) ?
The integral from-2 to-1 of 4/(x^2) is 2