What is the derivative of y=sqrt(7+9x) ?

The derivative of y=sqrt(7+9x) is 9/(2sqrt(7+9x))

What is the first derivative of y=sqrt(7+9x) ?

The first derivative of y=sqrt(7+9x) is 9/(2sqrt(7+9x))

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derivative of

y = 7 + 9 x

\frac{9}{2 7 + 9 x}

Solution steps

\frac{d}{d x} (7 + 9 x)

Apply the chain rule:

\frac{1}{2 7 + 9 x} \frac{d}{d x} (7 + 9 x)

= \frac{1}{2 7 + 9 x} \frac{d}{d x} (7 + 9 x)

\frac{d}{d x} (7 + 9 x) = 9

= \frac{1}{2 7 + 9 x} \cdot 9

Simplify

\frac{1}{2 7 + 9 x} \cdot 9 : \frac{9}{2 7 + 9 x}

= \frac{9}{2 7 + 9 x}

\frac{d}{d x} (5 sec (x) - 10 cos (x))

(x^{2} + 3) y^{^{'}} = x y

(x^{3} - 9 x)^{12}

x (\frac{d y}{d x}) - y = 3 x^{4}

\frac{d y}{d x}, 7 sin (x) + cos (y) = sin (x) cos (y)

What is the derivative of y=sqrt(7+9x) ?
The derivative of y=sqrt(7+9x) is 9/(2sqrt(7+9x))
What is the first derivative of y=sqrt(7+9x) ?
The first derivative of y=sqrt(7+9x) is 9/(2sqrt(7+9x))