What is the derivative of (4x^2-5x+9)/(3x+7) ?

The derivative of (4x^2-5x+9)/(3x+7) is (12x^2+56x-62)/((3x+7)^2)

What is the first derivative of (4x^2-5x+9)/(3x+7) ?

The first derivative of (4x^2-5x+9)/(3x+7) is (12x^2+56x-62)/((3x+7)^2)

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derivative of

\frac{4 x ^{2} - 5 x + 9}{3 x + 7}

\frac{12 x ^{2} + 56 x - 62}{( 3 x + 7 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 x ^{2} - 5 x + 9}{3 x + 7})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 4 x ^{2} - 5 x + 9 ) ( 3 x + 7 ) - \frac{d}{d x} ( 3 x + 7 ) ( 4 x ^{2} - 5 x + 9 )}{( 3 x + 7 ) ^{2}}

\frac{d}{d x} (4 x^{2} - 5 x + 9) = 8 x - 5

\frac{d}{d x} (3 x + 7) = 3

= \frac{( 8 x - 5 ) ( 3 x + 7 ) - 3 ( 4 x ^{2} - 5 x + 9 )}{( 3 x + 7 ) ^{2}}

Expand

(8 x - 5) (3 x + 7) - 3 (4 x^{2} - 5 x + 9) : 12 x^{2} + 56 x - 62

= \frac{12 x ^{2} + 56 x - 62}{( 3 x + 7 ) ^{2}}

x \to 2 lim (x^{2} - 3 x - 4)

y^{^{'}} = e^{(t + y)}

\frac{d y}{d x} = cos^{2} (+ sin (2 x))

\int (x + 7) e^{2 x + 3} d x

\int_{- 2}^{3} \frac{33}{x ^{4}} d x

What is the derivative of (4x^2-5x+9)/(3x+7) ?
The derivative of (4x^2-5x+9)/(3x+7) is (12x^2+56x-62)/((3x+7)^2)
What is the first derivative of (4x^2-5x+9)/(3x+7) ?
The first derivative of (4x^2-5x+9)/(3x+7) is (12x^2+56x-62)/((3x+7)^2)