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Popular >

d/(dθ)(a^2sin^2(θ)+b^2cos^2(θ))

Solution

\frac{d}{d θ} (a^{2} \cdot sin^{2} (θ) + b^{2} \cdot cos^{2} (θ))

Solution

a^{2} sin (2 θ) - b^{2} sin (2 θ)

Solution steps

\frac{d}{d θ} (a^{2} sin^{2} (θ) + b^{2} cos^{2} (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (a^{2} sin^{2} (θ)) + \frac{d}{d θ} (b^{2} cos^{2} (θ))

\frac{d}{d θ} (a^{2} sin^{2} (θ)) = a^{2} sin (2 θ)

\frac{d}{d θ} (b^{2} cos^{2} (θ)) = - b^{2} sin (2 θ)

= a^{2} sin (2 θ) - b^{2} sin (2 θ)

Popular Examples

f(x)=sin^{11}(x)

f (x) = sin^{11} (x)

(dy)/(dx)=-6(y^2-y)

\frac{d y}{d x} = - 6 (y^{2} - y)

derivative of (2ln(2x))/(2-3x)derivative of

\frac{2 ln ( 2 x )}{2 - 3 x}

derivative of (x^2+y^2^{2/3})

\frac{d}{d x} ((x^{2} + y^{2})^{\frac{2}{3}})

derivative of f(x)=ln(x^3+5x+3)derivative of

f (x) = ln (x^{3} + 5 x + 3)

Frequently Asked Questions (FAQ)

What is the d/(dθ)(a^2*sin^2(θ)+b^2*cos^2(θ)) ?
The d/(dθ)(a^2*sin^2(θ)+b^2*cos^2(θ)) is a^2sin(2θ)-b^2sin(2θ)
What is the first d/(dθ)(a^2*sin^2(θ)+b^2*cos^2(θ)) ?
The first d/(dθ)(a^2*sin^2(θ)+b^2*cos^2(θ)) is a^2sin(2θ)-b^2sin(2θ)