What is the limit as x approaches 2 of sqrt(x^4)-8 ?

The limit as x approaches 2 of sqrt(x^4)-8 is -4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 2 of sqrt(x^4)-8

x \to 2 lim (x^{4} - 8)

- 4

Solution steps

x \to 2 lim (x^{4} - 8)

Plug in the value

x = 2

= 2^{4} - 8

Simplify

2^{4} - 8 : - 4

= - 4

y^{^{''}} + y^{^{'}} - 6 y = 12 x - 50 sin (x)

\frac{d ^{2}}{d x ^{2}} (cos (7 x))

y^{^{'}} = 3 x (y + 4)^{2}

f (t) = t - 4

\int \frac{6 x ^{2} - 5 x + 8}{x ^{3} + 4 x} d x

What is the limit as x approaches 2 of sqrt(x^4)-8 ?
The limit as x approaches 2 of sqrt(x^4)-8 is -4