What is the integral from 2 to 7 of t^4ln(3t) ?

The integral from 2 to 7 of t^4ln(3t) is -671-32/5 ln(6)+16807/5 ln(21)

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integral from 2 to 7 of t^4ln(3t)

\int_{2}^{7} t^{4} ln (3 t) d t

- 671 - \frac{32}{5} ln (6) + \frac{16807}{5} ln (21)

Decimal Notation

9551.39046 \dots

Solution steps

\int_{2}^{7} t^{4} ln (3 t) d t

Compute the indefinite integral:

\int t^{4} ln (3 t) d t = \frac{1}{5} t^{5} ln (3 t) - \frac{t ^{5}}{25} + C

Compute the boundaries:

\int_{2}^{7} t^{4} ln (3 t) d t = \frac{16807}{5} ln (21) - \frac{16807}{25} - (\frac{32}{5} ln (6) - \frac{32}{25})

= \frac{16807}{5} ln (21) - \frac{16807}{25} - (\frac{32}{5} ln (6) - \frac{32}{25})

Simplify

= - 671 - \frac{32}{5} ln (6) + \frac{16807}{5} ln (21)

x^{- 9}

\int e^{r^{2}} r d r

\frac{d}{d x} (ln (2 x^{2} + y^{2}))

25 y y^{^{'}} - 4 x = 0

\frac{d}{d x} (ln (- 1))

What is the integral from 2 to 7 of t^4ln(3t) ?
The integral from 2 to 7 of t^4ln(3t) is -671-32/5 ln(6)+16807/5 ln(21)