What is (\partial)/(\partial x)(2x^3+4y-2z^2) ?

The answer to (\partial)/(\partial x)(2x^3+4y-2z^2) is 6x^2

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(\partial)/(\partial x)(2x^3+4y-2z^2)

\frac{\partial}{\partial x} (2 x^{3} + 4 y - 2 z^{2})

6 x^{2}

Solution steps

\frac{\partial}{\partial x} (2 x^{3} + 4 y - 2 z^{2})

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{3}) + \frac{\partial}{\partial x} (4 y) - \frac{\partial}{\partial x} (2 z^{2})

\frac{\partial}{\partial x} (2 x^{3}) = 6 x^{2}

\frac{\partial}{\partial x} (4 y) = 0

\frac{\partial}{\partial x} (2 z^{2}) = 0

= 6 x^{2} + 0 - 0

Simplify

= 6 x^{2}

\int 2 \cdot x \cdot ln (4 x) d x

\int y x d x

\int_{0}^{π} sin^{2} (t co) s^{4} t d t

\frac{d y}{d t} = 0.225 - \frac{y}{200}, y (0) = 90

(x^{2} + 1) \cdot e^{x - 1}

What is (\partial)/(\partial x)(2x^3+4y-2z^2) ?
The answer to (\partial)/(\partial x)(2x^3+4y-2z^2) is 6x^2