What is (\partial)/(\partial y)(cos(xyz)) ?

The answer to (\partial)/(\partial y)(cos(xyz)) is -sin(xyz)xz

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(\partial)/(\partial y)(cos(xyz))

\frac{\partial}{\partial y} (cos (x yz))

- sin (x yz) x z

Solution steps

\frac{\partial}{\partial y} (cos (x yz))

Treat

x, z

as constants

Apply the chain rule:

- sin (x yz) \frac{\partial}{\partial y} (x yz)

= - sin (x yz) \frac{\partial}{\partial y} (x yz)

\frac{\partial}{\partial y} (x yz) = x z

= - sin (x yz) x z

y^{^{''}} + 45 y^{^{'}} + 20 y = 0, y (0) = 1, y^{^{'}} (0) = 0

n = 1 \sum \infty n e^{3 n}

x \to 0 + lim (\frac{6}{x ^{2}})

\int \frac{x}{x ^{2} + 2} d x

4 x, 64 - x^{2}, [- 6.928, 0]

What is (\partial)/(\partial y)(cos(xyz)) ?
The answer to (\partial)/(\partial y)(cos(xyz)) is -sin(xyz)xz