What is the tangent of y=11-6e^x,(0,5) ?

The tangent of y=11-6e^x,(0,5) is y=-6x+5

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tangent of y=11-6e^x,(0,5)

tangent of

y = 11 - 6 e^{x}, (0, 5)

y = - 6 x + 5

Solution steps

Find the slope of

y = 11 - 6 e^{x} : \frac{d y}{d x} = - 6 e^{x}

Compute the slope of

y = 11 - 6 e^{x}

(0, 5) : m = - 6

Find the line with slope m=

- 6

and passing through

(0, 5) : y = - 6 x + 5

y = - 6 x + 5

x \to 0 lim (\frac{ln ( x )}{x - 1})

\int 21 arctan (x) d x

x \to 0 lim (\frac{e ^{x} - 1}{4 x})

\int x (a x^{2} + b)^{3} d x

\int - π sin (π x) d x

What is the tangent of y=11-6e^x,(0,5) ?
The tangent of y=11-6e^x,(0,5) is y=-6x+5