What is the solution for t+ye^{2ty}+te^{2ty}(dy)/(dt)=0 ?

The solution for t+ye^{2ty}+te^{2ty}(dy)/(dt)=0 is y=(ln(c_{1}-t^2))/(2t)

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t+ye^{2ty}+te^{2ty}(dy)/(dt)=0

t + y e^{2 t y} + t e^{2 t y} \frac{d y}{d t} = 0

y = \frac{ln ( c _{1} - t ^{2} )}{2 t}

Solution steps

t + y e^{2 t y} + t e^{2 t y} \frac{d y}{d t} = 0

Solve exact ODE:

y = \frac{ln ( c _{1} - t ^{2} )}{2 t}

y = \frac{ln ( c _{1} - t ^{2} )}{2 t}

\frac{\partial}{\partial x} (2 e^{- 2 x y} + x y^{3})

\frac{d}{d x} (\frac{sin ( x )}{1 + tan ( x )})

x + \frac{3}{x}, at x = 2

f (x) = 4 - 2 x

x \to 2 lim (\frac{( x ^{6} - 64 )}{x - 2})

What is the solution for t+ye^{2ty}+te^{2ty}(dy)/(dt)=0 ?
The solution for t+ye^{2ty}+te^{2ty}(dy)/(dt)=0 is y=(ln(c_{1}-t^2))/(2t)