What is the integral of sin(2)(θ)cos(θ) ?

The integral of sin(2)(θ)cos(θ) is sin(2)(θsin(θ)+cos(θ))+C

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integral of sin(2)(θ)cos(θ)

\int sin (2) (θ) cos (θ) d θ

sin (2) (θ sin (θ) + cos (θ)) + C

Solution steps

\int sin (2) θ cos (θ) d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin (2) \cdot \int θ cos (θ) d θ

Apply Integration By Parts

: θ sin (θ) - \int sin (θ) d θ

= sin (2) (θ sin (θ) - \int sin (θ) d θ)

\int sin (θ) d θ = - cos (θ)

= sin (2) (θ sin (θ) - (- cos (θ)))

Simplify

= sin (2) (θ sin (θ) + cos (θ))

Add a constant to the solution

= sin (2) (θ sin (θ) + cos (θ)) + C

x \to 1 lim (\frac{1 - x}{x ^{2} + 1})

\frac{d y}{d x}, x^{3} + y^{3} = 6 x y - 1

\int \frac{1}{x ^{3} + 2 x ^{2} + x} d x

\frac{1}{s ( ( s + 2 ) ^{2} + 1 )}

n = 1 \sum \infty 6 e^{- 8 n}

What is the integral of sin(2)(θ)cos(θ) ?
The integral of sin(2)(θ)cos(θ) is sin(2)(θsin(θ)+cos(θ))+C