What is the derivative of 1/(3x^5) ?

The derivative of 1/(3x^5) is -5/(3x^6)

What is the first derivative of 1/(3x^5) ?

The first derivative of 1/(3x^5) is -5/(3x^6)

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\frac{d}{d x} (\frac{1}{3 x ^{5}})

- \frac{5}{3 x ^{6}}

Solution steps

\frac{d}{d x} (\frac{1}{3 x ^{5}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (\frac{1}{x ^{5}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{3} \frac{d}{d x} (x^{- 5})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{3} (- 5 x^{- 5 - 1})

Simplify

\frac{1}{3} (- 5 x^{- 5 - 1}) : - \frac{5}{3 x ^{6}}

= - \frac{5}{3 x ^{6}}

f (x) = (\frac{sin ( x )}{x})^{2}

\int 4 x^{\frac{2}{3}} d x

\frac{\partial}{\partial y} (3 x + 2 x y^{2})

\int \frac{4}{( x ^{2} + 5 x - 14 )} d x

x \to 2 lim (2 x^{2} - 3)

What is the derivative of 1/(3x^5) ?
The derivative of 1/(3x^5) is -5/(3x^6)
What is the first derivative of 1/(3x^5) ?
The first derivative of 1/(3x^5) is -5/(3x^6)