What is the solution for y^'-3/x y=(y^4)/(x^7) ?

The solution for y^'-3/x y=(y^4)/(x^7) is y=(x^3)/(\sqrt[3]{-x^3+c_{1)}}

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y^'-3/x y=(y^4)/(x^7)

y^{^{'}} - \frac{3}{x} y = \frac{y ^{4}}{x ^{7}}

Solution steps

y^{'} (x) - \frac{3}{x} y = \frac{y ^{4}}{x ^{7}}

Solve Bernoulli ODE:

\frac{d}{d x} (4 sin^{2} (3 x))

y^{^{''}} + 10 y^{^{'}} + 25 y = e^{- 4 x} (x^{2} + 2 x - 4)

x^{^{''}} - 2 x = 0

\frac{d}{d x} (cos^{2} (e^{x}))

(7, - 2), (3, 5)

What is the solution for y^'-3/x y=(y^4)/(x^7) ?
The solution for y^'-3/x y=(y^4)/(x^7) is y=(x^3)/(\sqrt[3]{-x^3+c_{1)}}