What is the derivative of-6/(sqrt(x)) ?

The derivative of-6/(sqrt(x)) is 3/(x^{3/2)}

What is the first derivative of-6/(sqrt(x)) ?

The first derivative of-6/(sqrt(x)) is 3/(x^{3/2)}

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\frac{d}{d x} (- \frac{6}{x})

\frac{3}{x ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (- \frac{6}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 6 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 6 \frac{d}{d x} (x^{- \frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 6 (- \frac{1}{2} x^{- \frac{1}{2} - 1})

Simplify

- 6 (- \frac{1}{2} x^{- \frac{1}{2} - 1}) : \frac{3}{x ^{\frac{3}{2}}}

= \frac{3}{x ^{\frac{3}{2}}}

\int_{- 5}^{5} e d x

x \to 4 lim (\frac{4 - x}{x - 4})

x \to 1 lim (\frac{1}{( x ^{2} - 1 )})

\int_{- 4}^{0} f (x) d x

n = 1 \sum \infty cos^{n} (1)

What is the derivative of-6/(sqrt(x)) ?
The derivative of-6/(sqrt(x)) is 3/(x^{3/2)}
What is the first derivative of-6/(sqrt(x)) ?
The first derivative of-6/(sqrt(x)) is 3/(x^{3/2)}