What is the derivative of ln(2x^2+5) ?

The derivative of ln(2x^2+5) is (4x)/(2x^2+5)

What is the first derivative of ln(2x^2+5) ?

The first derivative of ln(2x^2+5) is (4x)/(2x^2+5)

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\frac{d}{d x} (ln (2 x^{2} + 5))

\frac{4 x}{2 x ^{2} + 5}

Solution steps

\frac{d}{d x} (ln (2 x^{2} + 5))

Apply the chain rule:

\frac{1}{2 x ^{2} + 5} \frac{d}{d x} (2 x^{2} + 5)

= \frac{1}{2 x ^{2} + 5} \frac{d}{d x} (2 x^{2} + 5)

\frac{d}{d x} (2 x^{2} + 5) = 4 x

= \frac{1}{2 x ^{2} + 5} \cdot 4 x

Simplify

\frac{1}{2 x ^{2} + 5} \cdot 4 x : \frac{4 x}{2 x ^{2} + 5}

= \frac{4 x}{2 x ^{2} + 5}

\int (1 + x + x^{2} + x^{3}) d x

\frac{d}{d x} (a sin (a x))

\int \frac{( 5 x ^{2} - 12 )}{( x ^{2} - 6 x + 13 ) ^{2}} d x

n = 1 \sum \infty \frac{1}{1 + n}

x y^{^{'}} - 4 y = 0

What is the derivative of ln(2x^2+5) ?
The derivative of ln(2x^2+5) is (4x)/(2x^2+5)
What is the first derivative of ln(2x^2+5) ?
The first derivative of ln(2x^2+5) is (4x)/(2x^2+5)