What is the d/(dy)(sqrt(y^2+1)) ?

The d/(dy)(sqrt(y^2+1)) is y/(sqrt(y^2+1))

What is the first d/(dy)(sqrt(y^2+1)) ?

The first d/(dy)(sqrt(y^2+1)) is y/(sqrt(y^2+1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d y} (y^{2} + 1)

\frac{y}{y ^{2} + 1}

Solution steps

\frac{d}{d y} (y^{2} + 1)

Apply the chain rule:

\frac{1}{2 y ^{2} + 1} \frac{d}{d y} (y^{2} + 1)

= \frac{1}{2 y ^{2} + 1} \frac{d}{d y} (y^{2} + 1)

\frac{d}{d y} (y^{2} + 1) = 2 y

= \frac{1}{2 y ^{2} + 1} \cdot 2 y

Simplify

\frac{1}{2 y ^{2} + 1} \cdot 2 y : \frac{y}{y ^{2} + 1}

= \frac{y}{y ^{2} + 1}

x \to 3 lim (\frac{2}{3 - 2})

\frac{d}{d x} f (x) = x^{\frac{- 11}{12}}

\int \frac{tan ( ln ( 2 x + 5 ) )}{2 x + 5} d x

\frac{\partial}{\partial s} (- cos (s - t))

\frac{d}{d x} (\frac{1}{2 ( 1 - x ) ^{\frac{3}{2}}})

What is the d/(dy)(sqrt(y^2+1)) ?
The d/(dy)(sqrt(y^2+1)) is y/(sqrt(y^2+1))
What is the first d/(dy)(sqrt(y^2+1)) ?
The first d/(dy)(sqrt(y^2+1)) is y/(sqrt(y^2+1))