What is (\partial)/(\partial x)(y-2x) ?

The answer to (\partial)/(\partial x)(y-2x) is -2

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(\partial)/(\partial x)(y-2x)

\frac{\partial}{\partial x} (y - 2 x)

- 2

Solution steps

\frac{\partial}{\partial x} (y - 2 x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (2 x) = 2

= 0 - 2

Simplify

= - 2

\int 12 sin^{2} (x) d x

x^{^{''}} + x^{^{'}} + 2 x = 4 e^{2 t}

\frac{d}{d x} (x^{x^{\frac{1}{2}}})

f (x) = 9 e^{x}

\frac{d y}{d x} = \frac{( x ^{3} + y ^{3} )}{x y ^{2}}

What is (\partial)/(\partial x)(y-2x) ?
The answer to (\partial)/(\partial x)(y-2x) is -2