What is the limit as x approaches 0 of ((x+3)^2-9)/x ?

The limit as x approaches 0 of ((x+3)^2-9)/x is 6

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limit as x approaches 0 of ((x+3)^2-9)/x

x \to 0 lim (\frac{( x + 3 ) ^{2} - 9}{x})

6

Solution steps

x \to 0 lim (\frac{( x + 3 ) ^{2} - 9}{x})

Simplify

\frac{( x + 3 ) ^{2} - 9}{x} : x + 6

= x \to 0 lim (x + 6)

Plug in the value

x = 0

= 0 + 6

Simplify

= 6

x (10 - 2 x) (16 - 2 x)

y^{^{'}} + 2 y = e^{x}

\frac{\partial}{\partial x} (z^{3})

\frac{\partial}{\partial s} (s t - 3)

\frac{\partial}{\partial x} (x^{2} + 2 y^{2} - 1)

What is the limit as x approaches 0 of ((x+3)^2-9)/x ?
The limit as x approaches 0 of ((x+3)^2-9)/x is 6