What is the x^2+4,-x^2-1,x=-2,x=3 ?

The x^2+4,-x^2-1,x=-2,x=3 is Domain: x=-2\lor x=3 Intercepts: None Asymptotes: None

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x^2+4,-x^2-1,x=-2,x=3

x^{2} + 4, - x^{2} - 1, x = - 2, x = 3

Domain : x = - 2 or x = 3

Intercepts : None

Asymptotes : None

Interval Notation

Domain : x = - 2 \cup x = 3

Solution steps

Domain of

{x^{2} + 4 : x = - 2, - x^{2} - 1 : x = 3} : x = - 2 or x = 3

Axis interception points of

{x^{2} + 4 : x = - 2, - x^{2} - 1 : x = 3} :

None

Asymptotes of

{x^{2} + 4 : x = - 2, - x^{2} - 1 : x = 3} :

None

f (x) = x^{2} ln (2 x)

x y^{^{'}} = y + 5 x^{2} sin (x)

f (x) = (2 x^{3} + 6 x) (4 x^{2} - 7 x + 11)

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} - 4})

\frac{\partial}{\partial y} (\frac{x + y}{x y - 1})

What is the x^2+4,-x^2-1,x=-2,x=3 ?
The x^2+4,-x^2-1,x=-2,x=3 is Domain: x=-2\lor x=3<br/>Intercepts: None<br/>Asymptotes: None