What is area y= 5/6 x^2,y= 11/6-x^2 ?

The answer to area y= 5/6 x^2,y= 11/6-x^2 is 22/9

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area y= 5/6 x^2,y= 11/6-x^2

area

y = \frac{5}{6} x^{2}, y = \frac{11}{6} - x^{2}

\frac{22}{9}

Decimal Notation

2.44444 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1} \frac{5}{6} x^{2} - (\frac{11}{6} - x^{2}) d x

Solve

\int_{- 1}^{1} \frac{5}{6} x^{2} - (\frac{11}{6} - x^{2}) d x : \frac{22}{9}

The area is:

= \frac{22}{9}

\frac{d}{d x} (e^{r x} r)

f (x) = x^{2} - 5 x + 5, at x = 6

x^{2} cos (x), 0.1

f (x) = - 25 x^{2} + 150 x - 182

\int 4 e^{- 0.2 x} d x

What is area y= 5/6 x^2,y= 11/6-x^2 ?
The answer to area y= 5/6 x^2,y= 11/6-x^2 is 22/9