What is the solution for (tdy)/(dt)-3y=sqrt(t) ?

The solution for (tdy)/(dt)-3y=sqrt(t) is y=-(2t^{1/2})/5+c_{1}t^3

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(tdy)/(dt)-3y=sqrt(t)

\frac{t d y}{d t} - 3 y = t

y = - \frac{2 t ^{\frac{1}{2}}}{5} + c_{1} t^{3}

Solution steps

\frac{t d y}{d t} - 3 y = t

Solve linear ODE:

y = - \frac{2 t ^{\frac{1}{2}}}{5} + c_{1} t^{3}

y = - \frac{2 t ^{\frac{1}{2}}}{5} + c_{1} t^{3}

\frac{\partial}{\partial z} (z e^{x yz})

x \to 0 lim (\frac{x + 1}{x - 1})

x^{- \frac{4}{5}}

\frac{3}{x}

\int \frac{x + 1}{x - 1} d x

What is the solution for (tdy)/(dt)-3y=sqrt(t) ?
The solution for (tdy)/(dt)-3y=sqrt(t) is y=-(2t^{1/2})/5+c_{1}t^3