What is the derivative of t^2+2t-3 ?

The derivative of t^2+2t-3 is 2t+2

What is the first derivative of t^2+2t-3 ?

The first derivative of t^2+2t-3 is 2t+2

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derivative of

t^{2} + 2 t - 3

2 t + 2

Solution steps

\frac{d}{d t} (t^{2} + 2 t - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{2}) + \frac{d}{d t} (2 t) - \frac{d}{d t} (3)

\frac{d}{d t} (t^{2}) = 2 t

\frac{d}{d t} (2 t) = 2

\frac{d}{d t} (3) = 0

= 2 t + 2 - 0

Simplify

= 2 t + 2

\frac{\partial}{\partial x} (\frac{( x - y )}{x})

n = 1 \sum \infty \frac{2}{3 n + 9}

\int_{l n (x)}^{1} sin^{3} (u) d u

y = x^{3} - 12 x^{2} + 32 x, - x^{3} + 12 x^{2} - 32 x

\int e^{\frac{x}{y}} d x

What is the derivative of t^2+2t-3 ?
The derivative of t^2+2t-3 is 2t+2
What is the first derivative of t^2+2t-3 ?
The first derivative of t^2+2t-3 is 2t+2