What is the tangent of y=x^4+2e^x,(0,2) ?

The tangent of y=x^4+2e^x,(0,2) is y=2x+2

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tangent of y=x^4+2e^x,(0,2)

tangent of

y = x^{4} + 2 e^{x}, (0, 2)

y = 2 x + 2

Solution steps

Find the slope of

y = x^{4} + 2 e^{x} : \frac{d y}{d x} = 4 x^{3} + 2 e^{x}

Compute the slope of

y = x^{4} + 2 e^{x}

(0, 2) : m = 2

Find the line with slope m=

2

and passing through

(0, 2) : y = 2 x + 2

y = 2 x + 2

f (x) = e^{0} (8 - 7 (0) + 5 (0)^{2})

\frac{d}{d x} (5 e)

\frac{\partial}{\partial y} ((e^{x} + e^{y})^{3})

y = 2 tan (cos (3 x)) + \frac{sin ( x ^{3} )}{x ^{2}}

x \to 7 - lim (\frac{x + 8}{x - 7})

What is the tangent of y=x^4+2e^x,(0,2) ?
The tangent of y=x^4+2e^x,(0,2) is y=2x+2