What is the solution for 1+ln(x)+y/x dx=(8-ln(x))dy ?

The solution for 1+ln(x)+y/x dx=(8-ln(x))dy is y=(xln(x))/(8-ln(x))+(c_{1})/(8-ln(x))

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1+ln(x)+y/x dx=(8-ln(x))dy

1 + ln (x) + \frac{y}{x} d x = (8 - ln (x)) d y

y = \frac{x ln ( x )}{8 - ln ( x )} + \frac{c _{1}}{8 - ln ( x )}

Solution steps

1 + ln (x) + \frac{y}{x} d x = (8 - ln (x)) d y

Solve linear ODE:

y = \frac{x ln ( x )}{8 - ln ( x )} + \frac{c _{1}}{8 - ln ( x )}

y = \frac{x ln ( x )}{8 - ln ( x )} + \frac{c _{1}}{8 - ln ( x )}

\frac{d}{d x} (x sin (x + y))

\int \frac{x}{x ^{2} + 2 x + 25} d x

\int \frac{5 x + 7}{4 x ^{2} + 12 x + 10} d x

f (t) = \frac{( e ^{x} + 5 x )}{5 x}

x^{2} + 2, 2 x + 6

What is the solution for 1+ln(x)+y/x dx=(8-ln(x))dy ?
The solution for 1+ln(x)+y/x dx=(8-ln(x))dy is y=(xln(x))/(8-ln(x))+(c_{1})/(8-ln(x))