What is the limit as x approaches 0 of x+1/x ?

The limit as x approaches 0 of x+1/x is diverges

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limit as x approaches 0 of x+1/x

x \to 0 lim (x + \frac{1}{x})

diverges

Solution steps

x \to 0 lim (x + \frac{1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (x + \frac{1}{x}) = \infty

x \to 0 - lim (x + \frac{1}{x}) = - \infty

= diverges

y = ln (x^{3}) x = 12

y = (\frac{x + 2}{x - 2})^{2}, (6, 4)

\int_{0}^{\frac{π}{2}} sin (2 t) d t

\int_{0}^{4} x + 1 d x

x \to 9 lim (3 - x)

What is the limit as x approaches 0 of x+1/x ?
The limit as x approaches 0 of x+1/x is diverges