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Popular >

derivative of (4x-3)/(sqrt(x))

Solution

derivative of

\frac{4 x - 3}{x}

Solution

\frac{4 x + 3}{2 x x}

Solution steps

\frac{d}{d x} (\frac{4 x - 3}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 4 x - 3 ) x - \frac{d}{d x} ( x ) ( 4 x - 3 )}{( x ) ^{2}}

\frac{d}{d x} (4 x - 3) = 4

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{4 x - \frac{1}{2 x} ( 4 x - 3 )}{( x ) ^{2}}

Simplify

\frac{4 x - \frac{1}{2 x} ( 4 x - 3 )}{( x ) ^{2}} : \frac{4 x + 3}{2 x x}

= \frac{4 x + 3}{2 x x}

Popular Examples

y^{''}-3/x y^'-4/(x^2)y=0

y^{^{''}} - \frac{3}{x} y^{^{'}} - \frac{4}{x ^{2}} y = 0

(\partial)/(\partial x)(17x^3y^2)

\frac{\partial}{\partial x} (17 x^{3} y^{2})

derivative of e^x(5x^2-2x+3)

\frac{d}{d x} (e^{x} (5 x^{2} - 2 x + 3))

(dy)/(dx)=(ysin(x))/(1-2y)

\frac{d y}{d x} = \frac{y sin ( x )}{1 - 2 y}

y^'=e^{y-x},y(0)=0

y^{^{'}} = e^{y - x}, y (0) = 0

Frequently Asked Questions (FAQ)

What is the derivative of (4x-3)/(sqrt(x)) ?
The derivative of (4x-3)/(sqrt(x)) is (4x+3)/(2xsqrt(x))
What is the first derivative of (4x-3)/(sqrt(x)) ?
The first derivative of (4x-3)/(sqrt(x)) is (4x+3)/(2xsqrt(x))