What is the derivative of cx^{-8} ?

The derivative of cx^{-8} is -(8c)/(x^9)

What is the first derivative of cx^{-8} ?

The first derivative of cx^{-8} is -(8c)/(x^9)

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\frac{d}{d x} (c x^{- 8})

- \frac{8 c}{x ^{9}}

Solution steps

\frac{d}{d x} (c x^{- 8})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= c \frac{d}{d x} (x^{- 8})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= c (- 8 x^{- 8 - 1})

Simplify

c (- 8 x^{- 8 - 1}) : - \frac{8 c}{x ^{9}}

= - \frac{8 c}{x ^{9}}

x^{2}

\frac{\partial}{\partial x} (e^{x y z^{6}})

\frac{\partial}{\partial x} (∣ x + y ∣ - 2)

\int (- 3 x^{- 2.5} - 7 x^{- 1}) d x

\frac{d}{d a} (\frac{sin ( a ) + cos ( a )}{sec ( a ) + csc ( a )})

What is the derivative of cx^{-8} ?
The derivative of cx^{-8} is -(8c)/(x^9)
What is the first derivative of cx^{-8} ?
The first derivative of cx^{-8} is -(8c)/(x^9)