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Popular >

y^'-2ty=4t^3

Solution

y^{^{'}} - 2 t y = 4 t^{3}

Solution

y = - 2 (t^{2} + 1) + c_{1} e^{t^{2}}

Solution steps

y^{'} (t) - 2 t y = 4 t^{3}

Solve linear ODE:

y = - 2 (t^{2} + 1) + c_{1} e^{t^{2}}

y = - 2 (t^{2} + 1) + c_{1} e^{t^{2}}

Popular Examples

integral from 4 to 5 of xsqrt(25-x^2)

\int_{4}^{5} x 25 - x^{2} d x

integral of (e^{-y})

\int (e^{- y}) d y

derivative of ((x-8))/(9x^2e^x)derivative of

\frac{( x - 8 )}{9 x ^{2} e ^{x}}

x^'=(1-x)*0.03-((0.03x))/((e^3-1))

x^{^{'}} = (1 - x) \cdot 0.03 - \frac{( 0.03 x )}{( e ^{3} - 1 )}

y^'-(2y)/x =-x^2y^2

y^{^{'}} - \frac{2 y}{x} = - x^{2} y^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'-2ty=4t^3 ?
The solution for y^'-2ty=4t^3 is y=-2(t^2+1)+c_{1}e^{t^2}