What is inverse oflaplace 4(1/(s^3)) ?

The answer to inverse oflaplace 4(1/(s^3)) is 2t^2

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inverse oflaplace 4(1/(s^3))

inverse laplace

4 (\frac{1}{s ^{3}})

2 t^{2}

Solution steps

L^{- 1} {4 (\frac{1}{s ^{3}})}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 4 L^{- 1} {\frac{1}{s ^{3}}}

L^{- 1} {\frac{1}{s ^{3}}} : \frac{t ^{2}}{2}

= 4 \cdot \frac{t ^{2}}{2}

Refine

4 \frac{t ^{2}}{2} : 2 t^{2}

= 2 t^{2}

n = 0 \sum \infty \frac{n ^{2}}{5 n}

6 x^{4}

\frac{\partial}{\partial u} (w arctan (uv))

\int sinh (t) d t

\int \frac{x ^{4}}{1 - x} d x

What is inverse oflaplace 4(1/(s^3)) ?
The answer to inverse oflaplace 4(1/(s^3)) is 2t^2