What is laplacetransform 5t-pi/3 ?

The answer to laplacetransform 5t-pi/3 is 5/(s^2)-pi/(3s)

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laplacetransform 5t-pi/3

laplace transform

5 t - \frac{π}{3}

\frac{5}{s ^{2}} - \frac{π}{3 s}

Solution steps

L {5 t - \frac{π}{3}}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= 5 L {t} - L {\frac{π}{3}}

L {t} : \frac{1}{s ^{2}}

L {\frac{π}{3}} : \frac{π}{3 s}

= 5 \cdot \frac{1}{s ^{2}} - \frac{π}{3 s}

Refine

5 \frac{1}{s ^{2}} - \frac{π}{3 s} : \frac{5}{s ^{2}} - \frac{π}{3 s}

= \frac{5}{s ^{2}} - \frac{π}{3 s}

\frac{d}{d x} (\frac{x - 9}{8 x ^{2} e ^{x}})

\frac{d y}{d x} = 4 x (x - 2)

n = 1 \sum \infty - \frac{1}{n}

\int e^{3 x^{2}} d x

\frac{\partial}{\partial θ} (r sin (θ))

What is laplacetransform 5t-pi/3 ?
The answer to laplacetransform 5t-pi/3 is 5/(s^2)-pi/(3s)