What is the derivative of c_{2}-3c_{1}-3c_{2}x ?

The derivative of c_{2}-3c_{1}-3c_{2}x is -3c_{2}

What is the first derivative of c_{2}-3c_{1}-3c_{2}x ?

The first derivative of c_{2}-3c_{1}-3c_{2}x is -3c_{2}

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\frac{d}{d x} (c_{2} - 3 c_{1} - 3 c_{2} x)

- 3 c_{2}

Solution steps

\frac{d}{d x} (c_{2} - 3 c_{1} - 3 c_{2} x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (c_{2}) - \frac{d}{d x} (3 c_{1}) - \frac{d}{d x} (3 c_{2} x)

\frac{d}{d x} (c_{2}) = 0

\frac{d}{d x} (3 c_{1}) = 0

\frac{d}{d x} (3 c_{2} x) = 3 c_{2}

= 0 - 0 - 3 c_{2}

Simplify

= - 3 c_{2}

\int \frac{8}{1 + x ^{2}} d x

\frac{\partial}{\partial x} (5 x^{4} + y^{7})

y \frac{d y}{d x} + 25 x = 0

x \to 4 lim (4 x + 48)

\frac{\partial}{\partial x} (- 3 x (- 9 - x - 2 y))

What is the derivative of c_{2}-3c_{1}-3c_{2}x ?
The derivative of c_{2}-3c_{1}-3c_{2}x is -3c_{2}
What is the first derivative of c_{2}-3c_{1}-3c_{2}x ?
The first derivative of c_{2}-3c_{1}-3c_{2}x is -3c_{2}