What is the derivative of ln(x^2-2x+1) ?

The derivative of ln(x^2-2x+1) is 2/(x-1)

What is the first derivative of ln(x^2-2x+1) ?

The first derivative of ln(x^2-2x+1) is 2/(x-1)

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\frac{d}{d x} (ln (x^{2} - 2 x + 1))

\frac{2}{x - 1}

Solution steps

\frac{d}{d x} (ln (x^{2} - 2 x + 1))

Apply the chain rule:

\frac{1}{x ^{2} - 2 x + 1} \frac{d}{d x} (x^{2} - 2 x + 1)

= \frac{1}{x ^{2} - 2 x + 1} \frac{d}{d x} (x^{2} - 2 x + 1)

\frac{d}{d x} (x^{2} - 2 x + 1) = 2 x - 2

= \frac{1}{x ^{2} - 2 x + 1} (2 x - 2)

Simplify

\frac{1}{x ^{2} - 2 x + 1} (2 x - 2) : \frac{2}{x - 1}

= \frac{2}{x - 1}

x \to - 19 lim (13 + x)

\int \frac{x ^{2}}{25 - x ^{2}} d x

\frac{d}{d x} (x^{y} + y^{x})

f (x) = x^{3} - 3 x + 2, at x = 3

n = 1 \sum \infty 7 (\frac{1}{10})^{n}

What is the derivative of ln(x^2-2x+1) ?
The derivative of ln(x^2-2x+1) is 2/(x-1)
What is the first derivative of ln(x^2-2x+1) ?
The first derivative of ln(x^2-2x+1) is 2/(x-1)