What is the limit as x approaches-1 of (x^2+1)/(x+1) ?

The limit as x approaches-1 of (x^2+1)/(x+1) is diverges

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limit as x approaches-1 of (x^2+1)/(x+1)

x \to - 1 lim (\frac{x ^{2} + 1}{x + 1})

diverges

Solution steps

x \to - 1 lim (\frac{x ^{2} + 1}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{x ^{2} + 1}{x + 1}) = \infty

x \to - 1 - lim (\frac{x ^{2} + 1}{x + 1}) = - \infty

= diverges

\int 6 x - x^{2} - 8 d x

\int x sin (\frac{1}{8} x) d x

\int \frac{( x ^{3} - 6 x - 20 )}{x + 5} d x

y = (x^{4}) + (\frac{3}{( x ^{2} )}), at x = - 1

y^{^{'}} + 2 y = t

What is the limit as x approaches-1 of (x^2+1)/(x+1) ?
The limit as x approaches-1 of (x^2+1)/(x+1) is diverges