What is the derivative of e^{-2x}+e^{3x} ?

The derivative of e^{-2x}+e^{3x} is -2e^{-2x}+e^{3x}*3

What is the first derivative of e^{-2x}+e^{3x} ?

The first derivative of e^{-2x}+e^{3x} is -2e^{-2x}+e^{3x}*3

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\frac{d}{d x} (e^{- 2 x} + e^{3 x})

- 2 e^{- 2 x} + e^{3 x} \cdot 3

Solution steps

\frac{d}{d x} (e^{- 2 x} + e^{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{- 2 x}) + \frac{d}{d x} (e^{3 x})

\frac{d}{d x} (e^{- 2 x}) = - 2 e^{- 2 x}

\frac{d}{d x} (e^{3 x}) = e^{3 x} \cdot 3

= - 2 e^{- 2 x} + e^{3 x} \cdot 3

e^{, at} sin (b \cdot t)

\int_{1}^{5} x^{3} d x

\int 2 x (x^{2} + 5)^{8} d x

\int 11 x d x

What is the derivative of e^{-2x}+e^{3x} ?
The derivative of e^{-2x}+e^{3x} is -2e^{-2x}+e^{3x}*3
What is the first derivative of e^{-2x}+e^{3x} ?
The first derivative of e^{-2x}+e^{3x} is -2e^{-2x}+e^{3x}*3