What is implicit (dy)/(dx),xy+3=y ?

The answer to implicit (dy)/(dx),xy+3=y is (dy)/(dx)=-y/(x-1)

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implicit (dy)/(dx),xy+3=y

implicit derivative

\frac{d y}{d x}, x y + 3 = y

\frac{d y}{d x} = - \frac{y}{x - 1}

Solution steps

x y + 3 = y

Treat

y

y (x)

Differentiate both sides:

x \frac{d y}{d x} + y = \frac{d y}{d x}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{y}{x - 1}

\frac{d y}{d x} = - \frac{y}{x - 1}

\int \frac{( x ^{7} )}{1 + x ^{16}} d x

\frac{\partial}{\partial x} (2 x^{3} y - 3 y^{2} z)

2 4 - x

\frac{d}{d x} (ka ln (\frac{x + d}{x - d}))

\frac{1}{2} cos (7 x)

What is implicit (dy)/(dx),xy+3=y ?
The answer to implicit (dy)/(dx),xy+3=y is (dy)/(dx)=-y/(x-1)