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Popular >

y^'+y=t

Solution

y^{^{'}} + y = t

Solution

y = t - 1 + \frac{c _{1}}{e ^{t}}

Solution steps

y^{'} (t) + y = t

Solve linear ODE:

y = t - 1 + \frac{c _{1}}{e ^{t}}

y = t - 1 + \frac{c _{1}}{e ^{t}}

Popular Examples

derivative of (sqrt(x)/(x+3))

\frac{d}{d x} (\frac{x}{x + 3})

integral of 1/(x^2sqrt(9+x^2))

\int \frac{1}{x ^{2} 9 + x ^{2}} d x

(x+2)sin(y)dx+xcos(y)dy=0

(x + 2) sin (y) d x + x cos (y) d y = 0

(dy)/(dx)=e^{-x^2},y(3)=5

\frac{d y}{d x} = e^{- x^{2}}, y (3) = 5

integral of (4-3x)^5+e^{2x+5}+sin(9x)

\int (4 - 3 x)^{5} + e^{2 x + 5} + sin (9 x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+y=t ?
The solution for y^'+y=t is y=t-1+(c_{1})/(e^t)