What is the integral from 0 to 2 of 1/(sqrt(x)) ?

The integral from 0 to 2 of 1/(sqrt(x)) is 2sqrt(2)

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integral from 0 to 2 of 1/(sqrt(x))

\int_{0}^{2} \frac{1}{x} d x

22

Decimal Notation

2.82842 \dots

Solution steps

\int_{0}^{2} \frac{1}{x} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{0}^{2}

= [2 x^{\frac{1}{2}}]_{0}^{2}

Apply radical rule:

= [2 x]_{0}^{2}

Compute the boundaries:

22

= 22

\frac{d}{d x} (sin^{n} (x))

\frac{d}{d x} (ln (\frac{( x - 1 )}{x + 1}))

4 x y^{3} y^{^{'}} = x^{4} + 4 y^{4}

\int 49 - x^{2} d x

\int \frac{x ^{5} - x ^{3} + 8 x}{x ^{4}} d x

What is the integral from 0 to 2 of 1/(sqrt(x)) ?
The integral from 0 to 2 of 1/(sqrt(x)) is 2sqrt(2)