What is area y=-x^2+16,x=-2,y=0,x=3 ?

The answer to area y=-x^2+16,x=-2,y=0,x=3 is 205/3

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area y=-x^2+16,x=-2,y=0,x=3

area

y = - x^{2} + 16, x = - 2, y = 0, x = 3

\frac{205}{3}

Decimal Notation

68.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} - x^{2} + 16 d x

Solve

\int_{- 2}^{3} - x^{2} + 16 d x : \frac{205}{3}

The area is:

= \frac{205}{3}

x \to 4 + lim (\frac{4}{x - 4})

\int e^{2 - 3 x} d x

\int \frac{1}{49 x ^{2} - 81} d x

x \to (0) + lim (3 x^{(\frac{x}{2})})

\frac{d}{d x} ((5 x^{2} + 3) (4 x - 3))

What is area y=-x^2+16,x=-2,y=0,x=3 ?
The answer to area y=-x^2+16,x=-2,y=0,x=3 is 205/3