What is the derivative of 2e^{cos(x}) ?

The derivative of 2e^{cos(x}) is -2e^{cos(x)}sin(x)

What is the first derivative of 2e^{cos(x}) ?

The first derivative of 2e^{cos(x}) is -2e^{cos(x)}sin(x)

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\frac{d}{d x} (2 e^{c o s (x)})

- 2 e^{c o s (x)} sin (x)

Solution steps

\frac{d}{d x} (2 e^{c o s (x)})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{c o s (x)})

Apply the chain rule:

e^{c o s (x)} \frac{d}{d x} (cos (x))

= e^{c o s (x)} \frac{d}{d x} (cos (x))

\frac{d}{d x} (cos (x)) = - sin (x)

= 2 e^{c o s (x)} (- sin (x))

Simplify

= - 2 e^{c o s (x)} sin (x)

\int x^{6} (x + 4) d x

n = 1 \sum \infty \frac{n}{n + 2}

y^{^{''}} + 12 y^{^{'}} + 85 y = 0

\int 2 e^{- 5 x} d x

- 2 x^{\frac{2}{3}} - 4

What is the derivative of 2e^{cos(x}) ?
The derivative of 2e^{cos(x}) is -2e^{cos(x)}sin(x)
What is the first derivative of 2e^{cos(x}) ?
The first derivative of 2e^{cos(x}) is -2e^{cos(x)}sin(x)