What is the limit as x approaches 0 of log_{e}(x^2) ?

The limit as x approaches 0 of log_{e}(x^2) is Does not exist

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of log_{e}(x^2)

x \to 0 lim (lo g_{e} (x^{2}))

Does not exist

Solution steps

x \to 0 lim (lo g_{e} (x^{2}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (lo g_{e} (x^{2})) = - \infty

x \to 0 - lim (lo g_{e} (x^{2})) =

Does not exist

= Does not exist

x \to 1 lim (x - 1 + 4)

t \cdot cos (3 t)

\frac{d}{d x} (x^{5} e^{4 x})

9000 e^{0.08 x} (- 0.08)

\frac{d}{d x} ((5 x - 1)^{3} (x^{2} + 1)^{5})

What is the limit as x approaches 0 of log_{e}(x^2) ?
The limit as x approaches 0 of log_{e}(x^2) is Does not exist