What is the slope of y= 1/(x-2),\at x=6 ?

The slope of y= 1/(x-2),\at x=6 is -1/16

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slope of y= 1/(x-2),\at x=6

slope

y = \frac{1}{x - 2}, at x = 6

- \frac{1}{16}

Solution steps

y = \frac{1}{x - 2}

In order to find the slope of the function, take the derivative of

\frac{1}{x - 2}

\frac{d}{d x} (\frac{1}{x - 2}) = - \frac{1}{( x - 2 ) ^{2}}

- \frac{1}{( x - 2 ) ^{2}}

Find the value of

- \frac{1}{( x - 2 ) ^{2}}

for

x = 6 : - \frac{1}{16}

- \frac{1}{16}

\frac{d}{d x} ((\frac{4}{5} x)^{5})

\int \frac{x}{( x ^{4} + 2 )} d x

t y^{^{'}} + 2 y = sin (t), y (\frac{π}{2}) = 7

x^{2} - 41, 7 - 2 x

\int sin (θ) sin (3 θ) sin (5 θ) d θ

What is the slope of y= 1/(x-2),\at x=6 ?
The slope of y= 1/(x-2),\at x=6 is -1/16