What is the sum from n=0 to infinity of (5^n)/(3^n) ?

The sum from n=0 to infinity of (5^n)/(3^n) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of (5^n)/(3^n)

n = 0 \sum \infty \frac{5 ^{n}}{3 ^{n}}

diverges

Solution steps

n = 0 \sum \infty \frac{5 ^{n}}{3 ^{n}}

n \to \infty lim (n (\frac{\frac{5 ^{n}}{3 ^{n}}}{\frac{5 ^{n + 1}}{3 ^{n + 1}}} - 1)) = - \infty

L < 1,

by the Raabe's test

= diverges

\frac{s}{s - 1}

\int (1 - 8 x) (ln (x) + 1) d x

6 x^{2} + x y + 6 y^{2} = 13, (1, 1)

y^{^{''}} + 9 y = 5 csc^{2} (3 t)

What is the sum from n=0 to infinity of (5^n)/(3^n) ?
The sum from n=0 to infinity of (5^n)/(3^n) is diverges