What is (\partial)/(\partial y)(2xy^3) ?

The answer to (\partial)/(\partial y)(2xy^3) is 6xy^2

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(\partial)/(\partial y)(2xy^3)

\frac{\partial}{\partial y} (2 x y^{3})

6 x y^{2}

Solution steps

\frac{\partial}{\partial y} (2 x y^{3})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x \frac{\partial}{\partial y} (y^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 x \cdot 3 y^{3 - 1}

Simplify

= 6 x y^{2}

y^{^{''}} - 8 y^{^{'}} + 16 y = 2 t e^{4 t}

e^{- \frac{x}{2}}, 3

k = 1 \sum \infty \frac{x ^{k}}{k !}

\frac{d}{d x} (\frac{- 3 x ^{6} - x ^{5} + 3 x ^{4}}{x ^{2}})

x y^{^{'}} + y = y^{2}

What is (\partial)/(\partial y)(2xy^3) ?
The answer to (\partial)/(\partial y)(2xy^3) is 6xy^2