What is the derivative of (2/pi)sin(pit),t ?

The derivative of (2/pi)sin(pit),t is 2cos(pit)

What is the first derivative of (2/pi)sin(pit),t ?

The first derivative of (2/pi)sin(pit),t is 2cos(pit)

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derivative of

(\frac{2}{π}) sin (π t), t

2 cos (π t)

Solution steps

\frac{d}{d t} (\frac{2}{π} sin (π t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{2}{π} \frac{d}{d t} (sin (π t))

Apply the chain rule:

cos (π t) \frac{d}{d t} (π t)

= cos (π t) \frac{d}{d t} (π t)

\frac{d}{d t} (π t) = π

= \frac{2}{π} cos (π t) π

Simplify

\frac{2}{π} cos (π t) π : 2 cos (π t)

= 2 cos (π t)

\frac{d}{d x} ((sin^{2} (x))^{2})

\int sin (6 x) cos (2 x) d x

\int cos^{4} (7 - x) sin (7 - x) d x

\frac{d y}{d x} = e^{3 y} sin (4 x)

n = 0 \sum \infty \frac{1}{n ^{2} + 2 n}

What is the derivative of (2/pi)sin(pit),t ?
The derivative of (2/pi)sin(pit),t is 2cos(pit)
What is the first derivative of (2/pi)sin(pit),t ?
The first derivative of (2/pi)sin(pit),t is 2cos(pit)