What is the solution for (dy)/(dx)+x^2y=x^2 ?

The solution for (dy)/(dx)+x^2y=x^2 is y=e^{-(x^3)/3+c_{1}}+1

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(dy)/(dx)+x^2y=x^2

\frac{d y}{d x} + x^{2} y = x^{2}

y = e^{- \frac{x ^{3}}{3} + c_{1}} + 1

Solution steps

\frac{d y}{d x} + x^{2} y = x^{2}

Solve separable ODE:

y = e^{- \frac{x ^{3}}{3} + c_{1}} + 1

y = e^{- \frac{x ^{3}}{3} + c_{1}} + 1

n = 1 \sum \infty \frac{4}{7 ^{n}} + \frac{3}{n}

(2 x y^{2} - 7) d x + (2 x^{2} y + 6) d y = 0

\frac{d}{d x} (ln (\frac{e ^{x}}{e ^{x} - 1}))

f (x) = x - 1, at x = 10

\frac{e ^{x}}{e ^{x} - e ^{- x}}

What is the solution for (dy)/(dx)+x^2y=x^2 ?
The solution for (dy)/(dx)+x^2y=x^2 is y=e^{-(x^3)/3+c_{1}}+1