What is (\partial)/(\partial y)(-5yz^4) ?

The answer to (\partial)/(\partial y)(-5yz^4) is -5z^4

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(\partial)/(\partial y)(-5yz^4)

\frac{\partial}{\partial y} (- 5 y z^{4})

- 5 z^{4}

Solution steps

\frac{\partial}{\partial y} (- 5 y z^{4})

Treat

z

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 5 z^{4} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= - 5 z^{4} \cdot 1

Simplify

= - 5 z^{4}

\frac{d}{d x} (ln (\frac{4}{x ^{3}}))

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x \to - 3 + lim (f (x))

\frac{8 x ^{2} + 8 x + 4}{x}

\int \frac{tan ^{3} ( x )}{sec ( x )} d x

What is (\partial)/(\partial y)(-5yz^4) ?
The answer to (\partial)/(\partial y)(-5yz^4) is -5z^4